66x^2+240x=-8

Solution for 66x^2+240x=-8 equation:

66x^2+240x=-8

We move all terms to the left:

66x^2+240x-(-8)=0

We add all the numbers together, and all the variables

66x^2+240x+8=0

a = 66; b = 240; c = +8;
Δ = b2-4ac
Δ = 2402-4·66·8
Δ = 55488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{55488}=\sqrt{18496*3}=\sqrt{18496}*\sqrt{3}=136\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-136\sqrt{3}}{2*66}=\frac{-240-136\sqrt{3}}{132}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+136\sqrt{3}}{2*66}=\frac{-240+136\sqrt{3}}{132}
$